-4.9x^2+229x+122=0

Solution for -4.9x^2+229x+122=0 equation:

-4.9x^2+229x+122=0

a = -4.9; b = 229; c = +122;
Δ = b2-4ac
Δ = 2292-4·(-4.9)·122
Δ = 54832.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(229)-\sqrt{54832.2}}{2*-4.9}=\frac{-229-\sqrt{54832.2}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(229)+\sqrt{54832.2}}{2*-4.9}=\frac{-229+\sqrt{54832.2}}{-9.8}
$